Finding Force and Steep Grade for a Train with Given Acceleration and Drag Force

In summary: So, the equation becomes: 25 * drag force = ma So, the force exerted by the locomotive on the first car is 25 times the drag force, which is 25 * 250v = 6250v.
  • #1
chenying
48
0

Homework Statement


A locomotive accelerates a 25-car train along a level track. Each car has a mass of 6.8e104 kg and is suject to a drag force f = 250v, where v is the speed in m/s and the force f is in N. At the instant when the speed of the train is 44 km/h, the acceleration is 0.20 m/s2.

(a) What is the force exerted by the locomotive on the first car?

(b) Suppose that the force found in part (a) is the greatest force the locomotive can exert of the train. What, then, is the steepest grade up which the locomotive can pull the train at 44 km/h?


Homework Equations



f=ma

The Attempt at a Solution



no attempt; no idea how to approach problem.
 
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  • #2
chenying said:

Homework Statement


A locomotive accelerates a 25-car train along a level track. Each car has a mass of 6.8e104 kg and is suject to a drag force f = 250v, where v is the speed in m/s and the force f is in N. At the instant when the speed of the train is 44 km/h, the acceleration is 0.20 m/s2.

(a) What is the force exerted by the locomotive on the first car?


Okay. So ma is the resultant force on the train.

Force exerted by train (F) - friction (250v) = Resultant force


Now read the part in bold and see if you can't find F


EDIT: for the second part, they are asking for an angle θ for which the train can produce a constant velocity of 44km/h. Draw the train on an inclined plane at an angle θ. Don't forget to take the weight of train into account.
 
Last edited:
  • #3
ok, but I am confused with whether the force of the train is equal to the force of the train on one car?
 
  • #4
chenying said:
ok, but I am confused with whether the force of the train is equal to the force of the train on one car?

You don't need to bother about the force on one car. The train is made up of 25 cars, the mass of the train is 25 * mass of one car.
 
  • #5
So then its basically this:

25 trains * 6.8e4 kg/train * .20 m/s^2 - 250 * 12.22222222m/s = ma

336944.444 = ma

is this the answer? I've entered this into webassign and it says its wrong.
 
  • #6
25 cars means 25 times the drag force too, right?
 

1. What is the formula for calculating the force of train cars?

The formula for calculating the force of train cars is force = mass x acceleration. This means that the force is equal to the product of the mass of the train car and its acceleration.

2. How do you determine the mass of a train car?

The mass of a train car can be determined by weighing the car on a scale. Alternatively, the manufacturer or train company may have the mass listed in the car's specifications or documentation.

3. What factors affect the force of train cars?

The force of train cars can be affected by various factors, such as the weight and speed of the train, the friction between the wheels and the tracks, and external forces such as wind resistance or slopes on the tracks.

4. How does the force of train cars impact the overall train's movement?

The force of train cars is an important factor in the overall movement of a train. The force generated by each car is combined to move the entire train forward, and any changes in force, such as stopping or starting, can affect the train's speed and momentum.

5. Can the force of train cars be manipulated or controlled?

The force of train cars can be manipulated or controlled by adjusting the train's speed, adding or removing cars, or changing the cargo's weight. However, it is important to ensure that the force is within safe and manageable limits to prevent accidents or damage to the train.

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