The discussion revolves around calculating the horizontal force required to move a box with a mass of 30 kg, given a coefficient of static friction of 0.75. Participants are attempting to clarify the problem statement and the relevant equations.
The discussion is ongoing, with participants seeking clarification on the problem setup and the calculations. Some guidance has been offered regarding the correct values for gravity and mass, but there is no consensus on the next steps to take.
There is a request for the exact wording of the problem statement, indicating potential discrepancies in understanding. Participants are also addressing errors in unit representation and calculations, which may affect their approach to the problem.
Much better. Now in your post #1, what does the 0.98 represent, and what does the 0.30 represent (including their units)?Infinite324 said:The mass of the garbage can is 30 kg. The coefficient of the static friction between the can and the ground is .75.
What is the horizontal force necessary to get the can moving?
It should be 9.8 m/s/s. How did the 30 kg become 0.30?Infinite324 said:.98 m/s/s represents gravity and sorry I typed it wrong. It should be 30 N
According to your understanding, you tell me. You almost had it right to start with.Infinite324 said:Wow yes 9.8 for Gravity. How should I continue then?
If you're not sure about this, you need to go back and review your text and/or notes. The objective of studying a course is so that you can understand the fundamentals (and use this to solve a wide array of problems), rather than just to solve one specific problem.Infinite324 said:Should I multiply (9.8)(30)(.75)?