What is the velocity of a car that falls off a cliff?

AI Thread Summary
To determine the velocity of a car that falls off a 53 m high cliff and lands 139 m away, the time of fall must first be calculated using the vertical distance and the acceleration due to gravity. The time taken for the fall is approximately 3.29 seconds. This time can then be used to find the horizontal velocity by applying the formula v = d/t, where d is the horizontal distance. The correct approach involves recognizing that the horizontal motion is independent of the vertical fall. Thus, the horizontal velocity can be accurately calculated using the derived time.
Maty
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Homework Statement



A car drives straight off the edge of a cliff that is 53 m high. The police at the scene of the accident note that the point of impact is 139 m from the base of the cliff. How fast was the car traveling when it went over the cliff?

Homework Equations



Distance=Acceleration*(Time^2) and any other distance, acceleration, velocity, time formulas.

The Attempt at a Solution



My attempt was to use the vertical distance and gravity to find the time it took to fall, and then somehow use that time (3.29s) to find the horizontal velocity. But I have no idea how to do that, and not even sure if I started it out right.
 
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Never mind, I had the right number (3.29s) but wrong idea. Just had to plug in that number in v=d/t to get the velocity... Durr.
 

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