Finding mass of an object on a spring, given Frequency

AI Thread Summary
The discussion revolves around calculating the mass of an object on a spring based on its oscillation frequencies before and after adding an additional mass. The initial frequency is 0.84 Hz, and after adding 730 g, the frequency drops to 0.65 Hz. The user attempted to use the formula m = k/(2πf)² but encountered errors leading to incorrect mass calculations. After multiple attempts, the user finally arrived at the correct mass value. The conversation highlights the importance of careful mathematical manipulation in physics problems.
Zach_Sch
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Homework Statement


A mass m at the end of a spring oscillates with a frequency of 0.84 Hz . When an additional 730 g mass is added to m, the frequency is 0.65 Hz .

Homework Equations


f*2pi = w
w = (k/m)^1/2
f = (1/2pi)*(k/m)^1/2

The Attempt at a Solution


I simply used the third equation twice, rearranging to the following:
m = k/(2pi*f)^2
using this equation two different times I ended up with:
m = k / (2pi*.84)^2
m + .73 = k / (2pi*.65)^2
I solved the above equations for m and came out with the wrong answer.

Any help is greatly appreciated! Thanks in advance : )
 
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Zach_Sch said:

Homework Statement


A mass m at the end of a spring oscillates with a frequency of 0.84 Hz . When an additional 730 g mass is added to m, the frequency is 0.65 Hz .

Homework Equations


f*2pi = w
w = (k/m)^1/2
f = (1/2pi)*(k/m)^1/2

The Attempt at a Solution


I simply used the third equation twice, rearranging to the following:
m = k/(2pi*f)^2
using this equation two different times I ended up with:
m = k / (2pi*.84)^2
m + .73 = k / (2pi*.65)^2
I solved the above equations for m and came out with the wrong answer.

Any help is greatly appreciated! Thanks in advance : )
Can you show your math at the end where you solve the two equations for m? That may help us spot any errors... :smile:
 
berkeman said:
Can you show your math at the end where you solve the two equations for m? That may help us spot any errors... :smile:
Haha, so I attempted to solve my systems of equations three different times and got a very large negative mass, I just attempted it again and got the correct answer.
Sorry about that ... cheers
 
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