Finding Max Compression of Spring with 500g Block

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Homework Help Overview

The problem involves a 500 g block sliding down a frictionless track and compressing a spring upon impact. The context is centered around energy conservation principles, specifically gravitational potential energy and spring potential energy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between gravitational potential energy and spring compression, with attempts to equate energies to find maximum compression. Questions arise regarding the validity of using velocity at impact as a maximum value and whether the approach taken is correct.

Discussion Status

Some participants express confidence in their calculations and reasoning, while others reflect on the simplicity of the energy conservation approach. There appears to be a productive exchange of ideas regarding the methods used to arrive at the solution.

Contextual Notes

Participants note the importance of understanding the transition from gravitational potential energy to spring potential energy, with some expressing concern over the complexity of the problem despite arriving at correct results.

AnnieF
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Homework Statement


A 500 g block is released from rest and slides down a frictionless track that begins 2.00 m above the horizontal. At the bottom of the track, where the surface is horizontal, the block strikes and sticks to a light spring with a spring stiffness constant 20.0 N/m. Find the maximum distance the spring is compressed.


Homework Equations



mgh= 1/2mv^2
1/2KA^2=1/2mvmax^2

The Attempt at a Solution



9.8(2)=1/2v^2
v^2=6.26m/s

1/2(20) A^2= 1/2(.5)(6.26)^2

A= .99 m


I did this because I figured that if I found the velocity when the box first hit the spring, it would be considered the maximum velocity since the spring is at equilibrium at that point in time. Then, since it asked for the maximum distance it would be compressed, I just found the amplitude. Is this right? I really hope so because that is what I did on my test...Thanks for the help.
 
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AnnieF said:

Homework Statement


A 500 g block is released from rest and slides down a frictionless track that begins 2.00 m above the horizontal. At the bottom of the track, where the surface is horizontal, the block strikes and sticks to a light spring with a spring stiffness constant 20.0 N/m. Find the maximum distance the spring is compressed.

Homework Equations



mgh= 1/2mv^2
1/2KA^2=1/2mvmax^2

The Attempt at a Solution



9.8(2)=1/2v^2
v^2=6.26m/s

1/2(20) A^2= 1/2(.5)(6.26)^2

A= .99 mI did this because I figured that if I found the velocity when the box first hit the spring, it would be considered the maximum velocity since the spring is at equilibrium at that point in time. Then, since it asked for the maximum distance it would be compressed, I just found the amplitude. Is this right? I really hope so because that is what I did on my test...Thanks for the help.
Correct. But it would have been easier simply to equate gravitational potential with spring energy.

mgh = \frac{1}{2}kx^2

x = \sqrt{2mgh/k} = \sqrt{2*.5*9.8*2/20} = .99 m.

AM
 


Thanks. I was going to do it like that but my mind was convinced that it had to be more difficult than that.
 


WOOOO HOOO! I did it right and I got 100 on my test! What an amazing day. :)
 

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