Finding momentum of a two-block system

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The discussion focuses on calculating the momentum of a two-block system consisting of a 3 kg block and a 7 kg block, each with specified velocities. The initial momentum calculation was incorrectly approached by combining mass and velocity without considering individual contributions to momentum. It was clarified that the total momentum should be the vector sum of the momenta of each block, accounting for their respective velocities. The importance of careful calculations in physics problems was emphasized, particularly in ensuring that each component of momentum is accurately represented. The consensus is that the total momentum remains constant in an isolated system, even if individual velocities change.
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Homework Statement


A system consists of a 3 kg block moving with velocity ‹ 14, 5, 0 › m/s and a 7 kg block moving with velocity ‹ −4, 6, 0 › m/s.

(a) What is the momentum of this two-block system?

(b) Next, due to interactions between the two blocks, each of their velocities change, but the two-block system is nearly isolated from the surroundings. Now what is the momentum of the two-block system?

Homework Equations


p(sys)=M(total)V(Centre of mass)

The Attempt at a Solution


I broke up the momentum into separate vector directions.
x=(3+7)(14+ -4)
x= 21*10
x=210

y=(3+7)(6+5)
y= 21*11
y=231

There is no velocity in the z direction, therefore momentum = <210,231,0>
And for part b, if the system is isolated, then even if the velocity changes, the total momentum of the system should remain constant. Therefore, the momentum should still be <210,231,0>

I was sure my understanding was right. I am not sure why this answer is wrong. Is it a fundamental flaw in my understanding?

[EDIT]: from information gained from this website, http://en.wikibooks.org/wiki/FHSST_Physics/Momentum/System

I am given to understand that the total momentum in a system in the sum of the momentums in the system. In this case, the correct answer would be to find the vector momentum of each object and add them together.

My question: how is the the total momentum? Is it because it takes into account the momentum of all objects inside the system, and as some parts of the momentum are negative or positive, it cancels those parts and leaves a weighted average of the momentums in the system? Thanks!
 
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cherry_cat said:
I broke up the momentum into separate vector directions.
x=(3+7)(14+ -4)
That's not the right equation. Figure out the contribution of each to the x component of the momentum separately, then add them together.
x= 21*10
3+7=21?!
I am given to understand that the total momentum in a system in the sum of the momentums in the system. In this case, the correct answer would be to find the vector momentum of each object and add them together.
Exactly so.
 
Thank you!

haruspex said:
3+7=21?!

I didn't even notice that. Just shows that I need to take more care in my problems when working. Thanks very much.
 
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