Finding normal boiling point given pressure and enthelpy.

AI Thread Summary
The discussion focuses on calculating the heat of vaporization and the normal boiling point of ammonia using provided temperature and pressure data. The user initially calculates the heat of vaporization as approximately 25.179 kJ/mol, aligning closely with textbook values. Confusion arises regarding the normal boiling point, which is defined as the temperature at which vapor pressure equals external pressure, specifically at standard atmospheric pressure (760 torr). The user realizes that to find the normal boiling point, they can set the pressure ratio in the equation to 1 and solve for temperature. Ultimately, they successfully derive the normal boiling point as approximately 239 K.
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Homework Statement


Given the following data, determine the heat of vaporization and normal boiling point of ammonia
Temp (K):
200
210
220
230
235

Pressure (respectively)(torr):
65.3
134.3
255.7
456.0
597.0



Homework Equations


ln(p2/p1)=-deltaH/R(1/t2-1/t1)


The Attempt at a Solution



I have calculated using the first two sets of data that deltaH should be 25.179kJ/mol. The books answer within 1kJ/mol, so I'm assuming that they just used different data to come up with it. Anyways, I'm having a problem on the second part of the question where it asks to come up with a normal boiling point. The normal boiling point is when the vapor pressure equals the external pressure, right? But I have no variable in this equation that will give me the normal boiling point. Do I use this equation for both portions to the question? I'm confused. I should be able to solve the problem, just need a little boost please.
 
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You have a function that correlates vapor pressure with temperature, yes?

What is the pressure at the normal boiling point?
 
So if the normal boiling point is where the vapor pressure equals the external pressure, I can just set p2/p1 to 1.

So I have ln1=-25.179/8.314(1/210-1/T) then T equals the normal boiling point? Eh, I'm confused.
 
webz said:
So if the normal boiling point is where the vapor pressure equals the external pressure, I can just set p2/p1 to 1.

No.

What is the difference between the definitions of "boiling point" and "normal boiling point"?
 
PhaseShifter said:
No.

What is the difference between the definitions of "boiling point" and "normal boiling point"?

Oh I get it now! The normal point is at STP. Ugh why didn't I see that before

ln(760/65.3)=-25719/8.314(1/x-1/200)=~239K

Thank you!
 
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