Finding out force from a relation of position

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SUMMARY

The discussion centers on calculating the force exerted on a 1 kg particle whose position is defined by the equation x = t(t-1)(t-2) m. The correct approach involves differentiating the position function twice to find acceleration, leading to the expression a = 4t - 6. The force can then be determined using Newton's second law, F = ma, where 'm' is the mass of the particle. The participant initially struggled with the differentiation but later resolved the issue independently.

PREREQUISITES
  • Understanding of basic calculus, specifically differentiation.
  • Familiarity with Newton's laws of motion.
  • Knowledge of kinematic equations and their applications.
  • Basic algebra for manipulating equations.
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  • Study the process of differentiation in calculus, focusing on polynomial functions.
  • Learn about Newton's second law of motion and its applications in physics.
  • Explore kinematic equations to understand motion in one dimension.
  • Practice solving problems involving force and acceleration using real-world examples.
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of applying calculus to physical problems.

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Homework Statement



A particle of 1kg loves along x acid such that it's position x varies with time t as x =t(t-1)(t-2) m find the force exerted on the particle at t=0,1,2

Homework Equations


Just given that position x varies with time t as x=t(t-1)(t-2)

The Attempt at a Solution


After opening the bracket, i tried to differentiate it twice to get relation of acceleration but the answer i m getting is incorrect...I m getting a=4t-6 am i correct?
 
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I just tried to solve it again and i solved it nvm..Thx
 

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