Finding Particular Solutions for Second Order Linear Differential Equations

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Homework Statement



Find particular solution for
y''+2y'+5y = 4(e^-t)cos2t

Homework Equations



y.c = C(e^-t)cos2t + C(e^-t)sin2t

The Attempt at a Solution



y.p (particular solution) = At(e^-t)cos2t + Bt(e^-t)sin2t does not work! Help please!
 
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Are you sure your y_p doesn't work? Why don't you show us what you're getting when you plug it into the ODE.
 
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reply oh i figured it out. thank you!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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