Finding path difference of EM waves received by radio telecopes

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Homework Help Overview

The discussion revolves around determining the path difference of electromagnetic waves received by radio telescopes, specifically focusing on the geometric relationships involved in the problem.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between path difference and angles using trigonometric functions, questioning the definitions and interpretations of path difference in the context of the problem.

Discussion Status

Some participants have acknowledged mistakes in their initial reasoning regarding the path difference, while others have offered tips for verifying results through extreme cases. The discussion appears to be productive, with participants actively engaging in clarifying concepts.

Contextual Notes

There is an indication of confusion regarding the definitions of path difference and how it relates to the angles involved in the problem setup.

songoku
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Homework Statement
Please see below
Relevant Equations
Trigonometry
1626158609238.png


My attempt:
1626158751799.png

I think ##x## is the path difference so by using trigonometry, I got ##x=d \sin \theta##

But my teacher said the answer is ##d \cos \theta##

What is my mistake? Thanks

Edit: Sorry, I found my mistake. My ##x## is not the path difference
 
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OK, well done.

Tip: Always check a result for extreme cases (like here: ##\theta = 0## and ##\theta = \pi/2##)

##\ ##
 
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songoku said:
My x is not the path difference
Well, it is the difference between the path lines, but not the path length difference.
 
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Thank you very much BvU and haruspex
 
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