Finding Position Vectors and Particle Locations in 3-Dimensional Motion

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Can someone please help me with this?

Homework Statement


A particle begin to travel (in 3-d dimension) at time t=pi with the direction vector d=-sin(t)i+cos(t)j+k

2. The attempt at a solution
Find the position vector r of that particle and the location of that particle at time t=2pi

I depressingly need some helps with this problem. You can just simply give me some idea or method and don't have to solve it step by step. Thanks a bunch!
 
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\frac{dx}{dt}= -sin(t)
\frac{dy}{dt}= cos(t)
\frac{dz}{dt}= 1[/itex]<br /> You can solve for x, y, and z by integrating. You will, however, need to know some &quot;initial condition&quot; to solve for the three &quot;constants of integration&quot; you will get. The problem says the particle starts moving at time t= pi. Doesn&#039;t the problem give a position for the particle at that time?
 
I'm sorry, my bad, the particle was traveling in the helical path r=cos(t)i+sin(t)+tk but at t=pi it changed and took the tangential path to the initial path. So I figured out it would travel on the direction of the velocity vector which I was given as the direction vector.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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