Finding potential difference to accelerate the ion

AI Thread Summary
To accelerate a He+ ion from rest to a speed of 2.0 * 10^6 m/s, a potential difference of -83,000 volts is required. The kinetic energy equation (K = (1/2)mv^2) is used to determine the necessary energy, while the relationship U = qV connects potential energy to potential difference. The mass of the He+ ion is calculated as 1.66 * 10^-27 kg. The calculations confirm that the derived potential difference is correct. This analysis effectively demonstrates the relationship between kinetic energy and potential difference in ion acceleration.
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Homework Statement


What potential difference is needed to accelerate a He + ion (charge +e, mass 4 u) from rest to a speed of 2.0 * 10^6 m/s?

Homework Equations


Kf + Uf = Ki + Ui
U = qV where V is potential difference (volts)

K = (1/2)mv^2

The Attempt at a Solution


I chose the rest point to be r = 0, so even with U = Kq_1q_2/r, it would equal zero at the start.
Then:
(1/2)mv^2 = -qV

V = (-1/2q)mv^2
= -(2q/)uv^2
m = u* 1.66*10^-27 kg/u = 1.66*10^-27 kg

V = -(2/(1.6*10^-19 Coulombs)) * (1.66*10^-27 kg)(2.0*10^6 m/s)^2
= -83000 volts

Is this right?
 
Last edited:
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Correct.
 
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