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Homework Statement
A generalized TdS-equation for systems of several types of "work-parts" and varying number of particles in multiple components, is given by
dU = TdS + \sum_{i}y_idX_i+\sum_{\alpha =1}^{c}\mu_\alpha dN_{\alpha}
Thus, its natural to regard the internal energy U (an extensive property), as a function of the extensive variables U, S, {X_i}, {N_{\alpha}}. Here U_\alpha is the chemical potential for component \alpha, and N_\alpha is the number of particles in component \alpha of the system (a number that can vary by dN_\alpha \neq 0). Thus we have
U = U(S, X_i, N_\alpha)
Because (U, S, X_i, N_\alpha) are all extensive properties, we have the following homogeneity condition
U(\lambda S, \lambda {X_i}, \lambda {N_\alpha}) = \lambda U(S, {X_i}, {N_\alpha})
Homework Equations
My question regards a special case of this, namely a one-component gass system (not an ideal gass!) with the following internal energy
U = U(S, V, N) = \frac{aS^3}{NV}
where a is a a constant with dimension K^3m^3/J^2.
Problem: find the pressure p, the temperature T and the chemical potential \mu of this gas expressed by (S, V, N). And then find the heat capacities at constant volume C_V and pressure C_p, expressed by (N, T, V ) and (N, T, p), respectively.
The Attempt at a Solution
The TdS-equation becomes
TdS = dU + pdV - \mu dN = C_vdT + \left[\left(\frac{\partial U}{\partial V}\right)_T + p\right]dV - \mu dN
But here I am completely at a loss.