Finding Product of z1z2 in Standard & Trig Forms

purplestar002
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Ok i am having a hard time with this one. Find the product z1z2 in standard form. Then write z1 and z2 in trig form and find their product again. Finally, convert the answer that is in trig form to standard form to show that the two products are equal.
z1= 1+i, z2= 4i
 
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Wow, this is a tough one! :rolleyes:

It's your homework, why not show us what you can do with it?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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