Finding range given impact velocity?

AI Thread Summary
A projectile impacts the ground at 65 m/s at a 25° angle below the horizontal, prompting a discussion on calculating its horizontal range. The key question is whether the initial and final velocities are equal in magnitude but differ in direction, which is affirmed for level ground without air resistance. Participants explore using initial horizontal velocity (Vix) and time of flight (Δt) to determine the range (Δx). The calculated horizontal range options are 170m, 330m, 780m, and 360m. The discussion concludes that launch and impact velocities are symmetrical under the specified conditions.
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A projectile shot over level ground hits the ground with a velocity of 65m/s at an angle of 25° below the horizontal. What was the horizontal range of the projectile?
170m
330m
780m
360m

If something is launched over a horizontal plane, does Vi=Vf? (same magnitude and velocity) (but different direction obviously).
Would I then be able to find Vix and Δt to find the Δx (range)?
 
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jerm174 said:
A projectile shot over level ground hits the ground with a velocity of 65m/s at an angle of 25° below the horizontal. What was the horizontal range of the projectile?
170m
330m
780m
360m

If something is launched over a horizontal plane, does Vi=Vf? (same magnitude and velocity) (but different direction obviously).
Would I then be able to find Vix and Δt to find the Δx (range)?

Welcome to the PF.

Yes, over level ground with no air resistance, the launch and impact velocities and angles should be symmetrical.
 
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