Finding Spring Constant for Oscillating Mass

AI Thread Summary
To find the spring constant k for a 2.0kg mass oscillating 10 times in 21.6 seconds, the correct frequency is calculated as f = 10/21.6, which equals approximately 0.463 Hz, not 2.16 Hz. The formula k = mω² can be applied, where ω is derived from the frequency. The conservation of mechanical energy equation is correctly set up, but when x=0, the term 0.5kx² can be eliminated. The discussion highlights the importance of careful calculation and understanding of oscillation principles.
Saladsamurai
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A 2.0kg mass attached to a spring makes 10 oscilations in 21.6s; its amplitude is .0320m

Find spring constant k. My question about this part is
frequency=(#of oscillations)/(#of seconds to complete) right?

So f=10/21.6s =2.16Hz?

So if k=m\omega^2
k=2(2\pi*2.16)^2
IT's the wording that gets me...

And to find speed at x=o I use conservation of mech energy

\frac{kx_m^2}{2}=\frac{mv^2}{2}+\frac{kx^2}{2}

and I can eliminate .5kx^2 since x=0...
 
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10/21.6 is not 2.16 (that's 21.6/10).

Other than that, your work looks right.
 
learningphysics said:
10/21.6 is not 2.16 (that's 21.6/10).

Other than that, your work looks right.

Wow...I'm a tool...

Thanks!
 
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