(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A plane flies horizontally @ 299 m/s relative to ground.

Altitude: 3450m, level terrain; neglect air resistance.

1: How far from the point vertically under the point of release does the object land (in meters)?

2: At what angle must the bomb be released so that it hits the target at time of release (in °)?

2. Relevant equations

t = (sqrt(Voy^2 + 2gh) - Voy) / -g

Range = Vox(t)

3. The attempt at a solution

Using the above, I correctly figured 7933.83 m for the range. It's the angle part that's screwing me.

Now, because the y-component of that object's velocity is zero at release, I was able to answer #1 without breaking anything down. But I have not a clue as to how to find that damn angle.

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# Homework Help: Finding the angle of release from a moving plane that drops an object X distance away

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