1. The problem statement, all variables and given/known data A plane flies horizontally @ 299 m/s relative to ground. Altitude: 3450m, level terrain; neglect air resistance. 1: How far from the point vertically under the point of release does the object land (in meters)? 2: At what angle must the bomb be released so that it hits the target at time of release (in °)? 2. Relevant equations t = (sqrt(Voy^2 + 2gh) - Voy) / -g Range = Vox(t) 3. The attempt at a solution Using the above, I correctly figured 7933.83 m for the range. It's the angle part that's screwing me. Now, because the y-component of that object's velocity is zero at release, I was able to answer #1 without breaking anything down. But I have not a clue as to how to find that damn angle.