Finding the Area Between Two Curves: Graphical vs. Algebraic Methods

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I know how to do this graphically, but I can't remember how to set it up the long way. The equations are:

y^2=x and y=x-2

I know it should be easy, but it's late and I can't think...
 
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stewe151 said:
I know how to do this graphically, but I can't remember how to set it up the long way. The equations are:

y^2=x and y=x-2

I know it should be easy, but it's late and I can't think...

Find the intersection points then set up the integral from the one intersection point to the other of the "larger" curve minus the "smaller" curve.
 
Solve for the points of intersection of the two curves:

x=y^2

and y=x-2 \Rightarrow x=y+2

the intersection of these curves occurs at the values of y such that

y^2=y+2 \Rightarrow y^2-y-2=(y+1)(y-2)=0

so y=-1,2 and recall that x=y+2,

so the points are: (1,-1) & (4,2)

The integrand is easiest as: rightmost curve - leftmost curve = (y+2) - y^2

and the integral is then \int_{y=-1}^{2} (y+2-y^2)dy
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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