grog
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Homework Statement
Find the area enclosed inside r=3 sin (theta)
Homework Equations
integral?
The Attempt at a Solution
basically, I took \int3sin\Theta from 0 to 2pi, then pulled the 3 out to get
3\int sin\Theta from 0 to 2pi and then
3[-cos(\Theta)] evaluated from 0 to 2pi.
that seems too easy. what am I missing?
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