Finding the Asymptotes of a Hyperbola

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Discussion Overview

The discussion focuses on finding the polar equations for the asymptotes of a hyperbola represented in a specific polar form. Participants explore the relationship between the polar and Cartesian representations of hyperbolas and the conditions for asymptotes.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant presents a polar equation for a hyperbola and inquires about the polar equations for its asymptotes.
  • Another participant notes that plotting the hyperbola with a computer also shows the asymptotes, suggesting a visual approach to understanding their behavior.
  • A different participant mentions the possibility of converting the polar equation to Cartesian coordinates, acknowledging the tedious nature of the process and offering to share resources from a book on the topic.
  • It is proposed that an asymptote occurs when the radius \( r \) approaches infinity, implying that the denominator of the polar equation must approach zero.

Areas of Agreement / Disagreement

Participants express various approaches to the problem, with no consensus on the specific polar equations for the asymptotes or the best method to derive them. The discussion remains unresolved regarding the exact formulation of the asymptotes.

Contextual Notes

Participants acknowledge the complexity of converting between polar and Cartesian coordinates and the potential challenges in deriving asymptotes from the given polar form.

tade
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Given a hyperbola of the form:

r=\frac{A}{1+Bsinθ+Dcosθ}

what are the polar equations for the asymptotes?
 
Last edited:
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Oddly, plotting this with a computer will result in the asymptotes being plotted as well.
 
You can always change it into cartesian coordinates but the work can be tedious. I have not done conics in polar plane in a long time, but I can add snapshots of of a book on how to do so If you would like.
 
An asymptote is going to necessarily have r going to infinity, so the denominator has to be going to zero.
 

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