Finding the best interval of solutions for N (using epsilon)

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The discussion centers on finding the best interval of solutions for N in the limit expression lim as x→-∞ (-5x/(x-2)) = -5. The relevant equation is |(-5x/(x-2)) - (-5)| < ε, which simplifies to |x-2| > 10/ε. The correct interpretation of the absolute value leads to the conclusion that the interval should be NE [-(10/ε) + 2, -∞) rather than NE [(10/ε) + 2, -∞). The confusion arises from the misapplication of absolute value and inequality signs.

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The problem is:

lim as x→- ∞ (-5x/x-2)=-5

And I have to find the best interval of solutions for N

Relevant equations:
if x>N then |(-5x/x-2)-(-5)|<ε

My attempt:

|(-5x/x-2) - (-5)|<ε

|-10/x-2|<ε

x-2< 10/ε

as x→-∞ we can assume that x-2<0

x-2<10/ε

x< (10/ε)+2

therefore, the interval should be NE [(10/ε) +2, -∞)

however, the answer says that it should be -2 not +2. I don't know what I am doing wrong, if anyone can help that would be great! Thanks!
 
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tesla93 said:
The problem is:

lim as x→- ∞ (-5x/x-2)=-5

Of course, you should write that fraction as -5x /(x-2) here. Use parentheses!

And I have to find the best interval of solutions for N

Relevant equations:
if x>N then |(-5x/x-2)-(-5)|<ε

My attempt:

|(-5x/x-2) - (-5)|<ε

|-10/x-2|<ε

At this step you have 10/|x-2| < ε

x-2< 10/ε

No. You should have |x-2| > 10/ε. You need absolute value signs and the inequality is reversed.

as x→-∞ we can assume that x-2<0

x-2<10/ε

If x - 2 < 0, what is |x-2|?
 

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