Finding the Coefficient of Kinetic Friction

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SUMMARY

The discussion centers on calculating the coefficient of kinetic friction (uk) for a 0.700 kg wood block attached to a spring with a spring constant (k) of 200 N/m. The block is compressed 4.7 cm and then stretches 2.5 cm beyond its equilibrium position. The key equation involves the work-energy principle, specifically relating non-conservative work to the change in energy, which includes the potential energy stored in the spring, expressed as 1/2kx^2. Participants emphasize the importance of correctly applying this principle to find the coefficient of kinetic friction.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Knowledge of the work-energy principle in physics
  • Familiarity with kinetic friction concepts
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the work-energy theorem in detail
  • Learn how to calculate potential energy in spring systems
  • Explore the relationship between friction and motion
  • Practice problems involving kinetic friction and spring dynamics
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of kinetic friction and energy conservation principles.

besenji
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This problem has been giving me some trouble, and I was wondering if anyone could help?

A 0.700 kg wood block is firmly attached to a very light horizontal spring (k = 200 N/m) as shown in the figure (Intro 1 figure) . This block-spring system, when compressed 4.7 cm and released, stretches out 2.5 cm beyond the equilibrium position before stopping and turning back.

What is the coefficient of kinetic friction between the block and the table?

I just can't seem to find the correct equation.

I know that it involves 1/2kx^2. I am just not sure how to find the uk using that.

Any bit of help is greatly appreciated.
 
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Hi besenji,

besenji said:
This problem has been giving me some trouble, and I was wondering if anyone could help?

A 0.700 kg wood block is firmly attached to a very light horizontal spring (k = 200 N/m) as shown in the figure (Intro 1 figure) . This block-spring system, when compressed 4.7 cm and released, stretches out 2.5 cm beyond the equilibrium position before stopping and turning back.

What is the coefficient of kinetic friction between the block and the table?

I just can't seem to find the correct equation.

I know that it involves 1/2kx^2. I am just not sure how to find the uk using that.

Any bit of help is greatly appreciated.

I would suggest using the equation that relates non-conservative work to the change in energy. What do you get?
 

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