Finding the combined centroid of two regions given the centroids of both regions

theBEAST
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Homework Statement


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The Attempt at a Solution


I tried to do this problem by taking the average of the y-bar centroid values but that gave me the wrong answer. I am only interesting in knowing why this method is incorrect.

Thanks!
 
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What is the definition of centroid? Your method would be valid if the areas of the two regions were equal.
 
It can be shown that the centroid of the union of two (non-overlapping) regions is the weighted average of the two centroids, weighted by the areas of the regions. That is, if the two regions have centroid (x_1, y_1) and (x_2, y_2) and have areas A_1 and A_2, respectively, then the centroid of the combined regions is at
\left(\frac{A_1x_1+ A_2x_2}{A_1+ A_2}, \frac{A_1y_1+ A_2y_2}{A_1+ A_2}\right)
 


theBEAST said:
I tried to do this problem by taking the average of the y-bar centroid values but that gave me the wrong answer.
As your grandmother should have taught you, don't take an average of averages. If an elephant and a flea get on opposite ends of a symmetric seesaw, will they balance? So where's their combined centroid?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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