Finding the curve to minimize a functional

  • Thread starter Thread starter Esran
  • Start date Start date
  • Tags Tags
    Curve Functional
Esran
Messages
73
Reaction score
0

Homework Statement



Find the curve y(x) that passes through the endpoints (0,0) and (1,1) and minimizes the functional I[y] = integral(y'2 - y2,x,0,1).

Homework Equations



Principally Euler's equation.

The Attempt at a Solution



We choose f{y,y';x} = y'2 - y2. Our partial derivatives are:

df/dy = -2y
df/dy' = 2y'

Euler's equation gives:

df/dy - d/dx(df/dy') = 0
-2y - 2y'' = 0

The general solution for this differential equation is:

y = A cos(x) + B sin(x)

To find A and B, we use our constraint that y(0) = 0 and y(1) = 1. Our curve is then y(x) = sin(x)/sin(1).

Have I done this problem correctly? If not, where did I go wrong?
 
Physics news on Phys.org
I don't see anything wrong with your method.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top