Finding the Derivative of y=x^3-3(x^2+pi^2): What's Wrong?

[SELFMADE]

Homework Statement

Find the derivative:

y=x^3-3(x^2+pi^2)

Homework Equations

The Attempt at a Solution

y'=3x^2-6x-6pi

But the book's answer emits -6pi

What am I doing wrong?

 

[Vagrant]

Pi is a constant. Derivative of Pi^2 with respect to x is zero.

 

[SELFMADE]

But it has power of two? Will that change anything?

So derivative of pi^n n-all real numbers is zero?

 

[Vagrant]

Pi=3.14
Pi^2=9.87
Pi^3=31 and so on
As you can see that rasing a constant to real number power will result in a constant. Thus the derivative with respect to x will remain zero.

Anyway I think you should recheck the question.

 

[SELFMADE]

Ok got it.

What you mean recheck the question

 

[Vagrant]

Well I don't think that y' is equal to -6pi for the given question. So recheck the question.

 

[SELFMADE]

 

[Vagrant]

Find the derivative:

y=x^3-3(x^2+pi^2)

y'=3x^2-6x-6pi

But the book's answer emits -6pi

Check this question. Neither answer is right.

 

[SELFMADE]

That was an attempt

First one is not even the answer its the problem

http://reactiondynamics.com/wp-content/uploads/2009/04/facepalm.gif

 

[Deneb Cyg]

Oh I think I understand what's going on here. I think SELFMADE meant that "the book's answer 'omits' -6pi rather than 'emits'." Thus giving y'=3x^2-6x as the answer in the book, which is correct if I'm not mistaken.

 

[SELFMADE]

lol normal sunday morning typo, guys, sorry.

 

[HallsofIvy]

I hate it when textbooks "emit" answers. You have to keep sweeping them up off the floor!