Finding the Direction of Resultant Vector: A Vector Addition Problem

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To find the resultant vector from the given angles (a = 20.8°, b = 54.0°, c = 29.7°), one must calculate the x and y components of each vector and sum them to obtain the resultant's components (Rx and Ry). The magnitude of the resultant vector is 1.9 units. The direction of the resultant vector should be measured counterclockwise from the positive x-axis, which can be determined using the arctangent function (tan⁻¹(Ry/Rx)). A rough sketch can aid in visualizing the angle. Clarification is needed regarding the reference figure mentioned in the problem.
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The question is find the resultant of the vectors shown in the figure below. (Take a = 20.8°, b = 54.0° and c = 29.7°.)

I got the resultant vector to be 1.9units, it also tells me to find the direction counterclockwise from the positive x-axis. I'm not sure how to do that, is it asking me the degrees? I'm just confused what the question is asking for.
 
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sycho2 said:
The question is find the resultant of the vectors shown in the figure below. (Take a = 20.8°, b = 54.0° and c = 29.7°.)

I got the resultant vector to be 1.9units, it also tells me to find the direction counterclockwise from the positive x-axis. I'm not sure how to do that, is it asking me the degrees? I'm just confused what the question is asking for.
Yes, once you find the magnitude of the resultant vector, usually by using trig to find the x and y components of each vector, summing those components into the Rx and Ry components of the resultant, then the angle of the resultant vector is the angle whose tangent is Ry/Rx. Be sure to draw a rough graphical sketch, and properly detrmine its angle as measured ccw from the positive x axis.
 
Um, what "figure below"?
 

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