Finding The Divergence Of A Vector Field

Baumer8993
Messages
45
Reaction score
0

Homework Statement


Find The Divergence Of The Vector Field:
< ex2 -2xy, sin(y^2), 3yz-2x>


Homework Equations


I know that divergence is ∇ dot F.


The Attempt at a Solution


When I did it by hand I got
2xex2 + 2ycos(y2) + 3y

However wolfram alpha says it should be

2xex2 + 2ycos(y^2) + y

The difference is the last y. So who is right? This is for a divergence theorem problem, but I do not have an answer key.
 
Physics news on Phys.org
When you worked out the first term, you forgot to differentiate the -2xy.
If you include this, your answer will agree with Wolfram.
 
Hi Baumer8993! :smile:

- 2xy ? :wink:
 
Oh wow, thank you for the help!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top