- #1
mr_coffee
- 1,629
- 1
A parallel-plate capacitor has a capacitance of 60 pF, a plate area of 130 cm2, and a mica dielectric ( = 5.4). At 60 V potential difference, calculate the following values.
(a) E in the mica
wrong check mark V/m
(b) the magnitude of the free charge on the plates
C
(c) the magnitude of the induced surface charge on the mica
C
I tried the following:
E = [Q/A]/(k*Eo);
E = (1e-12/.013)/(5.4)(8.85e-12);
E = 1.609 which is wrong.
I got Q by the following: C = QV; Q = C/V; 60e-12/60 = 1e-12
(a) E in the mica
wrong check mark V/m
(b) the magnitude of the free charge on the plates
C
(c) the magnitude of the induced surface charge on the mica
C
I tried the following:
E = [Q/A]/(k*Eo);
E = (1e-12/.013)/(5.4)(8.85e-12);
E = 1.609 which is wrong.
I got Q by the following: C = QV; Q = C/V; 60e-12/60 = 1e-12