Finding the Electric Field as a Result of Two Point Charges

AI Thread Summary
The discussion focuses on calculating the electric field at point (0,0,8) due to two point charges: a -3 µC charge at (0,0,4) and a +3 µC charge at (0,0,-4). The user attempts to find the electric field by adding the contributions from each charge but arrives at an incorrect total of -1498.33 instead of the expected 609. They also explore a different point (4,4,0) but again find discrepancies in their results, yielding 648.8 instead of 487. The user questions whether they are making a calculation error and expresses frustration about LaTex formatting issues. The thread highlights common challenges in electrostatics calculations and the importance of careful vector addition.
Jefferson
Messages
5
Reaction score
0

Homework Statement


There is a −3 µC point charge at (0,0,4) and a +3 µC point charge at (0,0,-4). What is the magnitude and direction of the electric field at point (0,0,8)? What is the magnitude and direction of the electric field at point (0,0,8)? [/B]

Homework Equations


E = \frac{ k_e q }{ r^2 }<b>[<b>/itex]</b></b>[/B]<br /> <br /> <h2>The Attempt at a Solution</h2> <br /> It should be as simple as just adding the electric field caused by each point charge.<br /> (0,0,8)[&lt;b&gt;/itex]&lt;/b&gt;:&lt;br /&gt; (0,0,8) - (0,0,4) = (0,0,4)&lt;b&gt;&lt;br /&gt; &lt;/b&gt;(0,0,8) - (0,0,-4) = (0,0,12)&lt;b&gt;&lt;br /&gt; \frac{ k_e&lt;/b&gt;&amp;lt;b&amp;gt;−3 \mu C (0,0,4) }{ 4^3} + &amp;lt;b&amp;gt;\frac{ &amp;lt;b&amp;gt;k_e&amp;lt;/b&amp;gt; &amp;lt;b&amp;gt;3 \mu C (0,0,12) }{ 12^3 }&amp;lt;/b&amp;gt;&amp;lt;/b&amp;gt;&amp;lt;/b&amp;gt;&lt;b&gt;&lt;b&gt;&lt;b&gt;&lt;br /&gt; &lt;br /&gt; -1685.625 + 187.29166 = -1498.33334&lt;br /&gt; However, the answer I should be getting (apparently) is 609&lt;br /&gt; &lt;br /&gt; (4,4,0):&lt;br /&gt; &lt;b&gt;&lt;b&gt;(4,4,0) &lt;/b&gt;- (0,0,4) = (4,4,-4)&lt;br /&gt; &lt;b&gt;(4,4,0)&lt;/b&gt; - (0,0,-4) = (4,4,4)&lt;br /&gt; &lt;br /&gt; &lt;b&gt;k&lt;sub&gt;e&lt;/sub&gt; &lt;b&gt;−3 µC (4,4,-4) / (4^2 + 4^2 + 4^2)^(3/2) + &lt;b&gt;k&lt;sub&gt;e&lt;/sub&gt; &lt;b&gt;3 µC &lt;b&gt;(4,4,4) / (4^2 + 4^2 + 4^2)^(3/2)&lt;br /&gt; &lt;br /&gt; &lt;b&gt;k&lt;sub&gt;e&lt;/sub&gt; &lt;b&gt;−3 µC (4,4,-4) / (48)^(3/2) + &lt;b&gt;k&lt;sub&gt;e&lt;/sub&gt; &lt;b&gt;3 µC &lt;b&gt;(4,4,4) / (48)^(3/2)&lt;br /&gt; &lt;br /&gt; (-324.4, -&lt;b&gt;324.4, &lt;b&gt;324.4) + (&lt;b&gt;324.4,&lt;b&gt;324.4,&lt;b&gt;324.4) = (0,0, 648.8)&lt;br /&gt; However, the answer I should be getting is 487&lt;br /&gt; &lt;br /&gt; Am I doing something wrong?&lt;br /&gt; (and why is it ignoring my LaTex tags?)&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;/b&gt;&lt;br /&gt; &lt;/b&gt;&lt;/b&gt;&lt;/b&gt;[/B]
 
Last edited:
Physics news on Phys.org
Oops, sorry, didn't mean to double post.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top