Finding the First Derivative of a Polynomial Function

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I've got f(x)=x^2-(7x^2)/2-9x+3

I need to find the first derivative of it but I get as far as 2x- but I'm stumped as to what to do with (7x^2)/2 Would I use the quotiant rule? Or should I somehow bring the 2 up to the top and if so how do I do that?
 
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Sethka said:
I've got f(x)=x^2-(7x^2)/2-9x+3

I need to find the first derivative of it but I get as far as 2x- but I'm stumped as to what to do with (7x^2)/2 Would I use the quotiant rule? Or should I somehow bring the 2 up to the top and if so how do I do that?

If you mean f(x) = x^2 + \frac {7x^2}{2} -9x + 3, I'm sure that you can see what the answer will be.

If on the other hand you mean f(x) = x^2 + \frac {7x^2}{2 - 9x} + 3, use quotient rule.
 
I guess I risk coming off really stupid but I do mean the first one (7x^2)/2 It looks so simple I know, but I'm not sure which direction to go with the 2. Sorry if I'm wasting your guys' time or anything, but I can't see what the answer should be.
 
treat 7/2 as a constant (which it is :)) and get the derivative of x^2
 
Oh! Thank you! Funny how the simplest things can seem so hard. I feel silly now.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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