Finding the Force Exerted on a Log Using Virtual Work Calculations

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Homework Help Overview

The discussion revolves around calculating the force exerted on a log using virtual work principles, specifically in the context of a fireplace tong. Participants are exploring how the equations related to virtual work apply to this mechanical scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to relate the equations of virtual work to the mechanics of the fireplace tong. Some are considering the system as a series of levers and questioning how moments and angles affect the forces involved.

Discussion Status

The discussion is ongoing, with some participants expressing confusion about the application of the equations and others providing insights into the moments and forces at play. There is a mix of attempts to clarify concepts and explore numerical results without reaching a consensus.

Contextual Notes

Participants are grappling with the relationship between the virtual work equations and the physical setup of the fireplace tong, indicating potential gaps in understanding the underlying mechanics and assumptions involved.

balogun
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Virtual work (fireplace thong)

Homework Statement


http://s2.photobucket.com/albums/y31/bambidurojay/?action=view&current=fireplacetong.jpg

I have been given a fireplace thong and need to determine the force exerted on a log.


Homework Equations


It is in the virtual work chapter of my textbook but I cannot see how the equations they have given me relate to the question.


The Attempt at a Solution


see above
 
Last edited:
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Think of it as a series of levers ( like individual see-saw or teeter-totter )

ps I think you mean 'tong', fireplace thong sounds very painful.
 
Still can't see how the equation U=intg[F costeta ds] or U=int[M dteta] apply to situation.
help appreciated please.
 
One has to work with moments (applied force and moment arm). F is applied about A and induces a moment (force) at C. C then applies a moment about D at N.

There are angles involved, since F is applied at some angle with respect to the moment arm (FA). And the force at C (from the moment with respect to AC) acts at an angle with respect to the moment arm CD.

Statically the moments induced by FB must be equal and opposite FA.
 
Didnt really understand your explanation but i was just playing around with the numbers and seem to have got the anwser

24/17 x17/17 x 17/6=N=4F

thats the right anwser but stiil don't understand it.
 

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