Finding the force on a spring (Fs)?

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To find the force on a spring (Fs), the equation Fs = mass × gravity is applicable, but the results must align with Hooke's Law, which states that Fs = -kx. The user provided data from a lab experiment with varying weights and corresponding spring extensions, but noted discrepancies in the expected linear relationship on the graph. Feedback indicated potential measurement errors, particularly with the extension values, suggesting corrections were needed for accurate calculations. After addressing a typing error, the user is encouraged to re-evaluate the data for consistency with the expected linearity of the graph.
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Homework Statement


I'm trying to find the force of a spring (Fs) from the mass of the weights, and the extension of the spring. The springs length without a weight attached was 5 cm. The lab we did had us put 5 different weights on the same spring, and graph the results.

My results from the lab:
0.05 kg, spring stretched 0.021 meters.
0.1 kg, spring stretched 0.055 meters.
0.2 kg, spring stretched 0.115 meters.
0.3 kg, spring stretched 0.18 meters.
0.4 kg, spring stretched 0.25 meters.

Now, I don't know how to figure out the Fs (force on the spring) on each of these 5 results.

Homework Equations



I'm asking for an equation that can help me. So far, Fs=-kx has proven useless at the moment.

The Attempt at a Solution


My lab partner used Fs=mass X gravity to find force spring. I'm not sure if this is correct, because on the graph (Fs vs extension (x) graph) the line is supposed to be linear and straight, but my graph with the plotted points looks nothing like that when the dots are connected.

Any help would be appreciated.
 
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Looks like you have some measurement errors. If it stretched 0.115 m with .2 kg, then with .1 kg, it ought to stretch half as much, or about 0.055 m or so. Did you miss a decimal point?
 
PhanthomJay said:
Looks like you have some measurement errors. If it stretched 0.115 m with .2 kg, then with .1 kg, it ought to stretch half as much, or about 0.055 m or so. Did you miss a decimal point?
Oh yes, you're right! Typing error, I fixed that now.

Should make a little bit more sense now.
 
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