Finding the Inductor in an RL Circuit

AI Thread Summary
To find the inductor in an RL circuit, the half-life formula t 1/2 = 0.693(L/R) is used. Rearranging this gives L = (R * t 1/2) / 0.693. For the RL circuit with a 22Ω resistor and a half-life of 64.00µs, the calculated inductance is approximately 79.69µH. In the RLC circuit with a 1000Ω resistor and a capacitance of 11.63µF, the inductance is approximately 8.22mH. These calculations help determine the inductor values needed for circuit analysis.
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Homework Statement



I'm trying to find the inductor

RL Circuit:
Resistor (22Ω), Inductor , Function Generator
Resistance (Ω): 24.7 Ω 50

RL Circuit Half-Life: 64.00µs

RLC Circuit, Resonance:
Resistor (1000Ω), Inductor , Function Generator
Resistance (Ω): 1080 Ω 50

Capacitance: 11.63µf
Sine Wave Frequency at Resonance (voltage plots): 1.960 Hz
Sine Wave Frequency at Resonance (Lissajous figures): 550 Hz


Homework Equations


I'm not sure since there are so many on my lab sheet, but is it: t 1/2= 0.693(L/R)


The Attempt at a Solution



rearrange to (R* t 1/2)/0.693= L ?
 
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For the RL circuit, (22* 64.00µs)/0.693= 79.69µHFor the RLC Circuit, (1000* 11.63µf)/0.693= 8.22mH
 
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