Finding the Length of an Astroid Curve in Calculus II

sristi
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Calculus II homework help...

Hi,
I am new to this forum and I found about this forum on talk.collegeconfidential.com. Well I have been having some trouble with my Calc II work . It would be great if someone could explain this problem to be

Find the total length of the astroid x=a (cos t)^3, y=a (sin t)^3, where a>0.

I think I know how to find the equation for the integral but I don't know how to find the limits.

Here is the work that I did so far:

x'=-3a cos^2 sin
y'= 3a sin^2 cos

I set those equal to zero to find the critical points. I got 0, pi/2, pi, 3pi/2, 2pi. Then I got stuck. I tried graphing it in the parametric mode in my calculator but I got a weird looking graph...

Any help would be appreciated. Thanks.
 
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It should be easy to see that the limits are t= 0, t= 2\pi. You graph should be a diamond with sides "bulging" inward. Because the graph is in all four quadrants, each of x, y must be both positive and negative and you only get that for sine and cosine with the variable going from 0 to 2\pi.
 
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Thank you.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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