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Homework Statement
An object is shot from the origin with a velocity of 40.0 m/s at an angle of 55.0 degrees above the horizontal. What is the location of the object 3.00 seconds later?
Homework Equations
All 2D motion equations - too many to list Ex:
V_x = v_0x + a_x t
V_y = v_0y + a_y t
The Attempt at a Solution
What I am having trouble with is the 3.0 seconds later part. I am not sure how to approach this one. I have to find the x displacement and then the angle \theta which is no problem to do when I know V_y and V_x.
So I tried this:
\Delta x = 40 cos(55)3.0 = 68.8m , but none of the answer choices match this. So I must be doing something wrong. I also can't get a correct answer for V_y and V_x with these I could plug them into the inverse tangent equation and get an angle. To find V_x I do this:
V_x = 40 cos (55) = 22.9
for V_y I do this :
V_y = 40 sin (55) - (9.80)(3.0^2) = -55.4
I am not sure that I am using the time variable correctly.