Finding the MME for p of Bin(n,p)

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Homework Statement



X1,X2,...,Xk ~iid Bin(n,p) find the MME (Method of Moments Estimator) for p

Homework Equations



E[X] = n⋅p
Var[X] = n⋅p⋅(1-p)

Var(X) = E[X2] - [E[X]]2

The Attempt at a Solution



Does this look correct?

n⋅p⋅(1-p) = E[X2] - n2⋅p2

E[X2] = n⋅p⋅(1-p) + n2⋅p2

\bar{X}=n⋅p

\bar{X}2 = n⋅p⋅(1-p) + n2⋅p2

\bar{X}2 = \bar{X}⋅(1-p) + \bar{X}⋅\bar{X}

\hat{p} = ((\bar{X})2 + \bar{X} - \bar{X}2) / \bar{X}

Thanks.
 
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thesandbox said:

Homework Statement



X1,X2,...,Xk ~iid Bin(n,p) find the MME for p

Homework Equations



E[X] = n⋅p
Var[X] = n⋅p⋅(1-p)

Var(X) = E[X2] - [E[X]]2

The Attempt at a Solution



Does this look correct?

n⋅p⋅(1-p) = E[X2] - n2⋅p2

E[X2] = n⋅p⋅(1-p) + n2⋅p2

\bar{X}=n⋅p

\bar{X}2 = n⋅p⋅(1-p) + n2⋅p2

\bar{X}2 = \bar{X}⋅(1-p) + \bar{X}⋅\bar{X}

\hat{p} = ((\bar{X})2 + \bar{X} - \bar{X}2) / \bar{X}

Thanks.

I'm not sure what "MME" stands for; In have seen the terms MMSE, MLE, etc., but not MME. Anyway, do you want to take the sample mean \bar{X} = \frac{\sum_{i=1}^k X_i}{k}? If so, do you want E (\bar{X}) \text{ and } \text{Var}( \bar{X})? If that is what you want to get, just use standard formulas for the mean and variance of \bar{X} in terms of the means and variances of the X_i . You will get formulas very different from what you wrote (although I must admit I do not know exactly what you were trying to do).

RGV
 
MME := Method of Moments Estimator
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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