Finding the Net Force Exerted by Water (of certain depth) on A Dam

AI Thread Summary
To find the net force exerted by water on a 200 m high dam with a 60 m water depth, the hydrostatic pressure equation is used, where atmospheric pressure cancels out. The relevant variables include the density of water (1,000 kg/m^3), gravitational acceleration (9.8 m/s^2), and the depth of water (60 m). The force is calculated using the integral of pressure over the area, but the width of the dam is not provided, complicating the calculation. Clarification is sought on whether the 200 m measurement refers to the dam's width, as only the water depth is crucial for determining the net force. The discussion emphasizes the importance of understanding the dimensions involved in the calculations.
Beginner@Phys
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Homework Statement

Evaluate the net force on a 200 -m high dam with a 60 mwater depth.

Homework Equations


P=F/A
p(hydrostatic pressure)=rhogh+patm

The Attempt at a Solution


The atmospheric pressure acts on both the dam and the water, so it cancels out of the equation. g=9.8m/s^2, rho=1,000 kg/m^3,d=60m

F=P*A => dF= integral(rhogh)*(wdy) = rho*g*d*w (y) Integrated from y=0 to y=200
=(1,000 kg/m^3 *9.8m/s^2*60m*200 w )-0

But, I was not given width, so how else can I find the net force acting on the dam. All I know is that it remains constant.
 
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Beginner@Phys said:

Homework Statement

Evaluate the net force on a 200 -m high dam with a 60 mwater depth.
Are you sure that 200 m is not the width of the dam? The only height that matters is the depth of the water.

F=P*A => dF= integral(rhogh)*(wdy) = rho*g*d*w (y) Integrated from y=0 to y=200
=(1,000 kg/m^3 *9.8m/s^2*60m*200 w )-0
Not sure what you're doing here.
 
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