Finding the Net Force on q0 from +5q and –3q Charges

Thread starter Roxiney
Start date Aug 30, 2010
Tags

Charges Force Net Net force

AI Thread Summary

To find the location on the x-axis where a third charge, q0, experiences no net force from the charges +5q and -3q, one must analyze the forces acting on q0 due to both charges. The force exerted by +5q is attractive towards the origin, while the force from -3q is repulsive. By applying Coulomb's law, F = k * (q1q2/r^2), the distances from q0 to each charge must be set up to determine the point where these forces balance each other out. The solution involves calculating the distances and equating the magnitudes of the forces to find the equilibrium point. Ultimately, this approach leads to identifying the specific location on the x-axis for q0.

Aug 30, 2010

Roxiney

Homework Statement

A point charge +5q is located at the origin, and a point charge –3q is located on the x-axis at D = 0.361 m. At what location on the x-axis will a third charge, q0, experience no net force from the other two charges?

Homework Equations

F = k * (q1q2/r^2)

The Attempt at a Solution

Physics news on Phys.org

Aug 30, 2010

rock.freak667

Homework Helper

You need to show some attempt.

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »