Finding the possible frequencies of a tuning fork

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The discussion revolves around calculating the possible frequencies of a tuning fork based on a vibrating wire's properties. The wire, with a mass of 0.0120 kg and a length of 2.05 m, vibrates under a tension of 202 N, yielding a fundamental frequency. A beat frequency of 5.10 Hz indicates that the tuning fork's frequency is close to the wire's frequency. Participants suggest using the beat frequency equation to find the two possible frequencies of the tuning fork, which should be calculated as the wire's frequency plus and minus the beat frequency. The correct approach involves determining the wire's frequency first and then applying the beat frequency to find the tuning fork's frequencies.
chris097
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Homework Statement



A 0.0120 kg, 2.05 m long wire is fixed at both ends and vibrates in its simplest mode under a tension of 202 N. When a tuning fork is placed near the wire, a beat frequency of 5.10 Hz is heard. What are the possible frequencies of the tuning fork? (enter the smaller frequency first) (It asks for 2 answers)


Homework Equations



f = √(TL/m)/2L
fb = |f1 - f2|


The Attempt at a Solution



I first found the frequency of the string using equation 1 then I simply thought that the frequency of the tuning fork would always be multiples of 5.10 Hz from the frequency of the fork. So i got answers like 50.4, 50.5...


Can anyone please help out?
Thanks!
 
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Just use the second equation you listed in section 2. you know f_b and f_1 so what can f_2 be?
 
willem2 said:
Just use the second equation you listed in section 2. you know f_b and f_1 so what can f_2 be?

I end up getting 50.4 and 55.5 Hz, which is wrong.
 
f - 5.1 and f + 5.1
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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