Finding the speed v of the proton

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    Proton Speed
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The discussion revolves around calculating the speed of a proton emitted from a stationary nucleus using conservation of momentum. The initial momentum is zero, leading to the equation where the mass of the nucleus and the emitted proton are considered. The user initially miscalculated by subtracting four mass units instead of one, mistakenly thinking of an alpha particle emission. After clarification, the correct approach involves only accounting for the single proton emitted. The user acknowledges the error and thanks others for their assistance.
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Homework Statement



image.jpg

Homework Equations


Principle of conservation of momentum,
Σpi=Σpf

The Attempt at a Solution


Since the nucleus is stationary, initial momentum is zero.
Unified atomic mass constant, a.m.u = 1.66 x 10^-27
Mass of the new nucleus: (A-4) x a.m.u
Mass of proton: 4 x a.m.u
0= ((A-4) x a.m.u )(u) + (4 x a.m.u )(-v)
4v = (A-4) u
v= (A/4 -1) u
So I chose A,
But the answer is B, where have I gone wrong?
 
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Why did you subtract 4 mass units from the atom when it only emitted a single proton? Were you thinking alpha particle?
 
gneill said:
Why did you subtract 4 mass units from the atom when it only emitted a single proton? Were you thinking alpha particle?
Oh yeah, I was. :nb)
thanks for the help :smile:
 

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