Finding the Unit Normal Vector at t=0: A Headache-Inducing Problem

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SUMMARY

The discussion centers on finding the unit normal vector at t=0 for the position vector r(t) = √2t i + e^t j + e^-t k. To determine the unit normal vector, users must first calculate the tangent vector T(t) using the formula T(t) = r'(t) / |r'(t)|. Subsequently, the normal vector N(t) is derived from the tangent vector's derivative, N(t) = T'(t) / |T'(t)|. The challenge lies in the complexity of these calculations, particularly the derivatives and magnitudes involved.

PREREQUISITES
  • Understanding of vector calculus, specifically derivatives of vector functions.
  • Familiarity with the concepts of tangent and normal vectors in 3D space.
  • Knowledge of magnitude calculations for vectors.
  • Proficiency in applying limits and evaluating functions at specific points.
NEXT STEPS
  • Study the process of calculating derivatives of vector functions in detail.
  • Learn about the geometric interpretation of tangent and normal vectors in vector calculus.
  • Explore examples of finding unit normal vectors for various parameterized curves.
  • Review the application of the chain rule in vector differentiation.
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Students and professionals in mathematics, physics, or engineering who are dealing with vector calculus and need assistance in understanding the computation of unit normal vectors.

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The position vector is r(t)= \sqrt{2}t\bar{i}+e^{t}\bar{j}+e^{-t}\bar{k} and it is asking for the unit normal vector at the parameter which is t=0. I have tried this problem many times and I guess it is all of the simplifying that is driving me bonkers!



2. I know that to find the tangent vector you would use T(t)=\frac{r'(t)}{magnitude of r'(t)}. From there, it gets crazy because you have to find the derivative and the magnitude of the tangent vector and pop it into the formula to find the Normal vector which is N(t)=\frac{T'(t)}{magnitude of T'(t)}. Then you just substitute 0 for all t's in the equation and get the unit normal vector.



3. I did not get very far in this problem and looking back at my work makes me get a head ache. If anyone can offer any assistance with this problem, that would be great. Thanks:]
 
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Normal vector (dot) Tangent vector = 0 usually if you don't care about the binormal ones.
 


Oh, I wasn't familiar with that formula, but for this one, I have to find the derivative of the position vector and put it in the tangent vector formula, and then from there, I have to put the derivative of the tangent vector into the normal vector formula. I'm hoping that someone can help me with this problem.
 

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