Finding the Value of B in a Simple Equation

  • Thread starter Thread starter abot
  • Start date Start date
AI Thread Summary
To find the value of B in the equation (1.5999A)^2 = B^2 + A^2, the user is struggling to match their answer with the book's solution of 1.247. It is suggested that two equations are needed to solve for two variables, and clarification is given that the book's answer might actually be "1.247A." The discussion emphasizes simplifying the equation by subtracting A^2 from both sides and then taking the square root. Ultimately, the focus is on correctly manipulating the equation to find B.
abot
Messages
17
Reaction score
0
HI, i can't solve this equation. I am solving for B the answer in the book does not match mine. PLZ help.


(1.5999A)^2= B^2 + A^2

the answer in the book is 1.247
 
Physics news on Phys.org
What is A? You need two equations to solve for two variables.
 
thats all i have. the parent equation was

.0251A=.0157sqrtB^2 + A^2
 
Are you absolutely sure the answer in the book isn't "1.247A"? :wink:

Anyway, just subtract A^2 from both sides and take a square root to get that answer.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top