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## Homework Statement

An object moves with constant acceleration 4.60 m/s2 and over a time interval reaches a final velocity of 10.0 m/s. If its initial velocity is −5 m/s, what is its displacement during the time interval? What is the total distance travelled?

a=4.60m/s^2

vi=-5 m/s

vf=10m/s

## Homework Equations

vf= (vi)+(a)(t)

deltax=(vi)(t) + 1/2(a)(t)^2

## The Attempt at a Solution

vf=vi+at

10=-5+(4.6)t

t=3.26 s

deltax= vit+1/2(a)(t)^2

deltax= (-5)(3.26)+1/2(4.6)(3.26)^2

deltax= 8.14 m (displacement)

total distance travelled = 8.14 m

the answer i got for displacement is correct but the total distance travelled is wrong and i can't figure out why. can anyone help me please?