Finding Tower 2 Height to Achieve 3x Velocity

AI Thread Summary
To determine the height of Tower 2 needed for an object to fall with a velocity three times greater than that of an object dropped from Tower 1, the relevant equation is vf^2 = vi^2 + 2ad. By setting the final velocity of the object from Tower 2 (vf2) to be three times that of Tower 1 (vf1), the equation can be rearranged to find the height. The derived formula indicates that the height of Tower 2 should be d = (3 * vf1^2) / (2a). This calculation assumes both objects are dropped from rest and fall under the influence of gravity. The final answer will depend on the height of Tower 1 and the acceleration due to gravity.
Frankenstein19
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Homework Statement


(I don't remember the EXACT problem because it was in an exam I took a few days ago but it was something like: If we drop the same object off of two towers, what does the height of Tower2 need to be if we want the object to fall is a velocity 3 times greater than the object falling off of tower1?

Homework Equations

The Attempt at a Solution


What I used was the vf^2 = vi^2 + 2ad and solved for d. (vf^2-vi^2)/2a = d and if vi = 0 then d=vf^2/2a

so the Height of tower 2 would have to be d=(3*vf^2)/2a, right?
 
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Close.

The question you are answering is: if the height of tower #1 is d meters, then what height does tower #2 need to be for the mass to reach triple the speed?
 
NascentOxygen said:
Close.

The question you are answering is: if the height of tower #1 is d meters, then what height does tower #2 need to be for the mass to reach triple the speed?
yes when it hits the ground
 
Frankenstein19 said:

Homework Statement


(I don't remember the EXACT problem because it was in an exam I took a few days ago but it was something like: If we drop the same object off of two towers, what does the height of Tower2 need to be if we want the object to fall is a velocity 3 times greater than the object falling off of tower1?

Homework Equations

The Attempt at a Solution


What I used was the vf^2 = vi^2 + 2ad and solved for d. (vf^2-vi^2)/2a = d and if vi = 0 then d=vf^2/2a

so the Height of tower 2 would have to be d=(3*vf^2)/2a, right?
If vf1 is the velocity of something dropped off Tower 1, then the velocity of something dropped off Tower 2, vf2 = 3 * vf1. That's how you write triple the first speed.
 
Frankenstein19 said:
yes when it hits the ground
So, what is the answer?
 
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