Finding Units of k in t = k√(h)/d² Equation | Log-Log Graphing Question

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The discussion centers on determining the units of the constant k in the equation t = k√(h)/d², where t is in seconds, and both d and h are in centimeters. The derived expression for k is k = (t)*(d²)/(h^0.5). Participants clarify the need to express units correctly, emphasizing the importance of using proper exponents for clarity. The simplification process involves understanding how to manipulate units, particularly with centimeters raised to fractional powers. Ultimately, the conversation highlights the significance of correctly expressing and simplifying units in physics equations.
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Question asked to find the units of k after you find the porpotionality statement



i ended up getting
t\propto\frac{\sqrt{h}}{d^2}
so i turned that into an equation and end up with
t=k\frac{\sqrt{h}}{d^2}
solved for and found it on average to be 30 now the question is asking what the units are for k... lol hmm t is in s d and h are in cm

would it be s/cm^1.5 ?? lol..
 
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Keep the corresponding units with each number. You will first obtain,
k = (t)*(d^2)/(h^0.5),

Now in that form, show the units and simplify if possible.
 
i have no idea what cm^.5 is lol

s*cm2/cm^.5 simplifies?
 
Sorry! said:
i have no idea what cm^.5 is lol

s*cm2/cm^.5 simplifies?

Apparantly, t is in units of seconds (s);
d is in units of centimeters (cm);
h is in units of centimeters also (cm).

Not clear is do you need UNITS or DIMENSIONS.

You did not express your units with the proper exponents in your numerator. The "2" needs to be expressed as an exponent. That is the purpose of the "^" symbol.
What you have could be better simplified if needed, using laws of exponents (knowing that you have centimeter^2 as part of your numerator. How you simplify, or if you simplify no further is up to you, or depends on what is expected in your course.
 
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