Finding vC(t) for a Critical Damping RLC Circuit

AI Thread Summary
To find vC(t) for a critically damped RLC circuit, the initial conditions provided are a capacitor voltage of 15 V and an inductor current of 6 mA. The differential equation yields roots of -5000, leading to the general solution v(t) = C_1*e^(-5000t) + C_2*t*e^(-5000t). Initial conditions are applied to determine constants, where v(0) gives C_1 = 15 V and the derivative at t=0+ leads to a calculation for C_2. A discrepancy arises in the value of C_2, suggesting a potential error in the application of initial conditions or the interpretation of the current's relationship to voltage change. Understanding the correct method to solve for these constants is crucial for accurately determining vC(t).
MattHorbacz
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Homework Statement


Figure_P08.44.jpg

In the circuit in the following figure, the resistor is adjusted for critical damping. The initial capacitor voltage is 15 V, and the initial inductor current is 6 mA and R=1250 ohms

Find vC(t) for t≥0.
Express your answer in terms of t, where t is in milliseconds.

Homework Equations



i=c*dv/dt

The Attempt at a Solution


the only part of this problem i am not getting is solving for the constants with the given initial conditions... the 2 roots to the differential equation are -5000. so:
v(t)=C_1*e^(-5000t)+C_2*t*e^(-5000t)
and
dv/dt [at t=0+]=-5000*C_1+C_2=i/c=(6*10^-3)A/(320*10^-9 F)=18750 volts/s
v(0)=C_1=15V
so C_2 -5000*15=18750...C_2=93750
but apparently C_2 is actually equal to 56250...If the equation was C_2-5000*15=-18750, then i would get 56250...where am i going wrong?
 
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As the charge flows away from the capacitor, I=-dQ/dt= - C dV/dt.

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