Finding Velocity and Height of Wedge After Block Release

imdiskid06
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A small block of mass .5kg is released form rest at the top of a curved-shaped frictionless wedge of mass 3 kg , which sits on a frictionless horizontal surfces. When the block leaves the wedge, its velocity is 4 m/s to the right. Find the velocity of the wedge after the block reaches the horizontal surface. What is the height of the wedge?
 
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imdiskid06 said:
A small block of mass .5kg is released form rest at the top of a curved-shaped frictionless wedge of mass 3 kg , which sits on a frictionless horizontal surfces. When the block leaves the wedge, its velocity is 4 m/s to the right. Find the velocity of the wedge after the block reaches the horizontal surface. What is the height of the wedge?
1. Use conservation of momentum:MV+mv=0.
2. Use conservation of energy:MV^2+mv^2=2mgH.
 
hello everyone!

i am doing an investigation on the inverse square law of radiation, and i have plotted a graph of 1/rsquared angainst intensity of light. I have one point which for when the detector is closest to the point source (bulb) that is far from the line of best fit to the right side of the graph. how do i explain this?
 
You may be so close to the bulb that it no longer looks like a point source.
That would be if distance were not large compared with the radius of the bulb.
 
well the distance between the bulb and the detector was 0.05m. the radius of the bulbs was approx 9mm. help me
 
does any-one know of any applications of the inverse law. could you appoint me a website link
 
Meir Achuz said:
You may be so close to the bulb that it no longer looks like a point source.
That would be if distance were not large compared with the radius of the bulb.
That answers your question.
When you are that close, the inverse square law does not apply.
A website won't change that.
 
could you give some mathematical proof.
 
hello,

i need to know the mathematics involving the inverse law is used in predicting floods and their impact.
 
  • #10
Could you give me some examples where the inverse law is used.
 
  • #11
Meir Achuz said:
1. Use conservation of momentum:MV+mv=0.
2. Use conservation of energy:MV^2+mv^2=2mgH.
Why is it 2mgH?
 
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