Finding Volume Triple Integral

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SUMMARY

The discussion focuses on calculating the volume of the region bounded by the equation x² + y² = 36, z = x, and the xy-plane using a triple integral. The initial attempt involved integrating dz, dx, and dy with specific bounds, but resulted in an incorrect answer. The error was identified as a misunderstanding of the bounds for the variables, specifically that the bounds should be defined for x and y rather than dx and dy. A diagram is recommended to visualize the correct bounds for integration.

PREREQUISITES
  • Understanding of triple integrals in multivariable calculus
  • Familiarity with cylindrical coordinates
  • Knowledge of the equations of surfaces and their intersections
  • Ability to sketch and interpret geometric regions in three dimensions
NEXT STEPS
  • Review the concept of triple integrals in multivariable calculus
  • Learn about cylindrical coordinates and their applications in volume calculations
  • Practice sketching regions defined by equations like x² + y² = r²
  • Explore common mistakes in setting up bounds for multiple integrals
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable integrals, as well as educators looking to clarify common misconceptions in volume calculations.

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Homework Statement


Find the volume of area the area bounded by x^2+y^2=36, z=x and below the xy plane


Homework Equations





The Attempt at a Solution


I did a triple integral dzdxdy,
where dz is bound between x and 0
dx is bound between 0 and (36-y^2)^(1/2)
and dy is bound between 0 and 6
and got the incorrect answer.
Where did I go wrong here?
 
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You got only half of the correct value, right? Try to draw a diagram of what your bounds correspond to.
Btw, it's not 'dx' etc. that's bound. It's x etc.
 

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