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Finding Volume Triple Integral

  1. Nov 5, 2013 #1
    1. The problem statement, all variables and given/known data
    Find the volume of area the area bounded by x^2+y^2=36, z=x and below the xy plane


    2. Relevant equations



    3. The attempt at a solution
    I did a triple integral dzdxdy,
    where dz is bound between x and 0
    dx is bound between 0 and (36-y^2)^(1/2)
    and dy is bound between 0 and 6
    and got the incorrect answer.
    Where did I go wrong here?
     
  2. jcsd
  3. Nov 5, 2013 #2

    haruspex

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    You got only half of the correct value, right? Try to draw a diagram of what your bounds correspond to.
    Btw, it's not 'dx' etc. that's bound. It's x etc.
     
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