Find the volume of area the area bounded by x^2+y^2=36, z=x and below the xy plane
The Attempt at a Solution
I did a triple integral dzdxdy,
where dz is bound between x and 0
dx is bound between 0 and (36-y^2)^(1/2)
and dy is bound between 0 and 6
and got the incorrect answer.
Where did I go wrong here?