Finding Volume Using Integration: Revolving Functions Around a Line

EngnrMatt
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Homework Statement



Find the volume of the solid formed by revolving the functions: y=x2 and y=1 about the line y=6

Homework Equations



∏∫(ro2-ri2)dx

The Attempt at a Solution



I found the outer radius to be (1-x2)-6 and my inner radius to be -6. Also, the limits of integration were -1 and 1. Plugging it all in got -224/15. This is obviously wrong because it is negative, and the positive value didn't work either. Does anyone have a clue on how to do this?
 
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EngnrMatt said:

Homework Statement



Find the volume of the solid formed by revolving the functions: y=x2 and y=1 about the line y=6

Homework Equations



∏∫(ro2-ri2)dx

The Attempt at a Solution



I found the outer radius to be (1-x2)-6 and my inner radius to be -6. Also, the limits of integration were -1 and 1. Plugging it all in got -224/15. This is obviously wrong because it is negative, and the positive value didn't work either. Does anyone have a clue on how to do this?

Isn't the inner radius the distance from y=1 to y=6? Isn't that 5? What's the outer radius?
 
Yes, you are right. I see now, the outer radius will be the distance between y=6 and the lower function and the inner will be the distance between y-6 and the upper function. It worked by the way, thanks.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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