Finding Volume Using Triple Integrals: A Brief Guide

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SUMMARY

The discussion focuses on calculating the volume between the function z=4-x²-y² and the x/y plane using triple integrals. The user contemplates the correct limits of integration and whether to convert to polar coordinates, ultimately proposing to integrate in the order of dz, dy, and dx. The integration setup includes the expression V=4∫₀^{θ₀}∫₀^{rₘ} (4-r²)r dr dθ, indicating a method to simplify the calculation by leveraging symmetry in the first quadrant.

PREREQUISITES
  • Understanding of triple integrals in calculus
  • Familiarity with polar coordinates transformation
  • Knowledge of volume calculation under surfaces
  • Experience with integration limits and bounds
NEXT STEPS
  • Study the application of triple integrals in volume calculations
  • Learn about converting Cartesian coordinates to polar coordinates
  • Explore the concept of symmetry in integration
  • Practice solving similar problems involving paraboloids and integration limits
USEFUL FOR

Students and educators in calculus, particularly those focusing on multivariable calculus and volume calculations using triple integrals.

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Homework Statement



i have to find the volume between the function z=4-x^2-y^2 and the x/y plane

The Attempt at a Solution



I think I should be fine with the limits of integration but am not 100% confident what I am integrating.

is it 4-x^2-y^2-z??

or 4-x^2-y^2?
 
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So I'm just going to integrate dv I think this might be correct. my bounds would be x=0->sqrt(y^2-4) then y=0->sqrt(z-4) then z=0->4. And then I would integrate in this order. Is this correct?
 
Why not convert to polar coordinates? Then z=4-r^2 right? I assume you mean positive z, the paraboloid above the x-y plane. It's symmetrical so you could just integrate in the first quadrant and multiply by four:

V=4\int_0^{\theta_0}\int_0^{r_m} (4-r^2)rdrd\theta

Can you understand how I did that and come up with the values for \theta_0 and r_m?
 

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